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Softball: The conference post season tournament is different than I thought.

Plainosooner

Sooner starter
Oct 20, 2002
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There will be two round robins of three teams.

Group A will be conference champ -- OU, plus fourth place Texas and whoever ends up fifth. Could be any of KU, Tech or Iowa State, because of the rain out in game three between Kansas and Texas in Lawrence last weekend.

The other bracket will be second and third which will be OSU and Baylor, not sure which will be which. And the sixth place team. Same deal, Tech, KU or Iowa State.

Each group will have three games between each of the three. And the one winner from each bracket will play the one from the other bracket, one game for the tournament title.

So OU will likely play Texas for the Group A winner, and if they win two, will play the other Group winner.

I thought we'd only have to play two to win the tournament, but it takes three wins.

Baylor beat Texas tonight, so they are a game ahead of OSU in the loss column, but have two games left to play. OSU has won. Since they beat OSU two out of three, they'll be the second seed if they beat Texas Saturday or Sunday. But they'll have to prove it again.

If Iowa State has been playing pretty well. If they face Texas, whom they beat two or three in Austin, It might be OU vs ISU for the Group winner. Not sure what they'll do with a three way tie at 1-1 apiece.
 
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OU's group is set: Texas and Iowa State join OU in group A. .

Group B will be Baylor, who lost to Texas in Austin this afternoon, OSU and KU or Tech. If Kansas beats Iowa State tomorrow, Tech is out. If Kansas loses, getting swept, then Tech joins OSU and Baylor in group B.

The tournament starts Friday morning and will be finished in two days. According to the official site, there are six games scheduled Friday.. But last night, they said the that winners played a one game final. From the XII site, the group winners will play two out of three. If Baylor and OU advance, it will give both a chance to build up some RPI stats.
 
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